xfs/614: determine the sector size of the fs image by doing a test format

In some cases (such as xfs always_cow=1), the configuration of the test
filesystem determines the sector size of the filesystem that we're going
to simulate formatting.  Concretely, even if TEST_DEV is a block device
with 512b sectors, the directio geometry can specify 4k writes to avoid
nasty RMW cycles.  When this happens, mkfs.xfs will set the sector size
to that 4k accordingly, but the golden output selection is wrong.  Fix
this.

Signed-off-by: Darrick J. Wong <djwong@kernel.org>
Reviewed-by: Christoph Hellwig <hch@lst.de>
Signed-off-by: Zorro Lang <zlang@kernel.org>

diff --git a/tests/xfs/614 b/tests/xfs/614
index 2a799fbf3ed71ccf0e1582cc72e1711aaf558e9a..e182f073fddd64346a8a781327478dcf3abfd121 100755 (executable)
--- a/tests/xfs/614
+++ b/tests/xfs/614
@@ -25,13 +25,16 @@ _require_test
 $MKFS_XFS_PROG 2>&1 | grep -q concurrency || \
        _notrun "mkfs does not support concurrency options"
 
-test_dev_lbasize=$(blockdev --getss $TEST_DEV)
-seqfull=$0
-_link_out_file "lba${test_dev_lbasize}"
-
+# Figure out what sector size mkfs will use to format, which might be dependent
+# upon the directio write geometry of the test filesystem.
 loop_file=$TEST_DIR/$seq.loop
-
 rm -f "$loop_file"
+truncate -s 16M "$loop_file"
+$MKFS_XFS_PROG -f -N "$loop_file" | _filter_mkfs 2>$tmp.mkfs >/dev/null
+. $tmp.mkfs
+seqfull=$0
+_link_out_file "lba${sectsz}"
+
 for sz in 16M 512M 1G 2G 16G 64G 256G 512G 1T 2T 4T 16T 64T 256T 512T 1P; do
        for cpus in 2 4 8 16 32 40 64 96 160 512; do
                truncate -s "$sz" "$loop_file"