xfs/201: use min_dio_alignment size to replace 512b

This case use hard-code 512, but in 4k sector size device,
it will fail.

So I call _min_dio_alignment() to get the sector size, then
replace `512`.

Signed-off-by: Zorro Lang <zlang@redhat.com>
Reviewed-by: Dave Chinner <dchinner@redhat.com>
Signed-off-by: Dave Chinner <david@fromorbit.com>

diff --git a/tests/xfs/201 b/tests/xfs/201
index 88829d3448f8afbd6a2fbf016f59ea711f7478fe..921d2a3ffbfe0de54656d4709db13854b480786b 100755 (executable)
--- a/tests/xfs/201
+++ b/tests/xfs/201
@@ -32,15 +32,6 @@ here=`pwd`
 tmp=/tmp/$$
 status=1       # failure is the default!
 
-do_pwrite()
-{
-       offset=`expr $1 \* 512`
-       end=`expr $2 \* 512`
-       length=`expr $end - $offset`
-
-       xfs_io -d -f $file -c "pwrite $offset $length" >/dev/null
-}
-
 _cleanup()
 {
        umount $SCRATCH_MNT
@@ -57,6 +48,17 @@ _supported_os Linux
 
 file=$SCRATCH_MNT/f
 
+min_align=`_min_dio_alignment $SCRATCH_DEV`
+
+do_pwrite()
+{
+       offset=`expr $1 \* $min_align`
+       end=`expr $2 \* $min_align`
+       length=`expr $end - $offset`
+
+       xfs_io -d -f $file -c "pwrite $offset $length" >/dev/null
+}
+
 _require_scratch
 
 _scratch_mkfs_xfs >/dev/null 2>&1