It's doesn't matter, since it's a deterministic permutation of hte value
and we're checking for equality, but avoid the filestore-specific
nibblewise key to avoid confusion.
Signed-off-by: Sage Weil <sage@redhat.com>
hobject_t end = objects.back().get_boundary();
objects.pop_back();
- if (objects.back().get_filestore_key() != end.get_filestore_key()) {
+ if (objects.back().get_hash() != end.get_hash()) {
candidate_end = end;
boundary_found = true;
}